Last Call Review of draft-ietf-trill-pseudonode-nickname-06

Request Review of draft-ietf-trill-pseudonode-nickname
Requested rev. no specific revision (document currently at 07)
Type Last Call Review
Team General Area Review Team (Gen-ART) (genart)
Deadline 2015-09-15
Requested 2015-09-01
Authors Hongjun Zhai, Tissa Senevirathne, Radia Perlman, Mingui Zhang, Li Yizhou
Draft last updated 2016-01-29
Completed reviews Genart Last Call review of -05 by Russ Housley (diff)
Genart Last Call review of -06 by Russ Housley (diff)
Secdir Last Call review of -05 by Carl Wallace (diff)
Opsdir Last Call review of -05 by Linda Dunbar (diff)
Rtgdir Early review of -05 by Russ White (diff)
Assignment Reviewer Russ Housley 
State Completed
Review review-ietf-trill-pseudonode-nickname-06-genart-lc-housley-2016-01-29
Reviewed rev. 06 (document currently at 07)
Review result Almost Ready
Review completed: 2016-01-29


I am the assigned Gen-ART reviewer for this draft.  The General Area
Review Team (Gen-ART) reviews all IETF documents being processed by
the IESG for the IETF Chair.  Please treat these comments just like
any other last call comments.  For more information, please see the
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Document: draft-ietf-trill-pseudonode-nickname-06
Reviewer: Russ Housley
Review Date: 2015-09-11
IETF LC End Date: 2015-09-01
IESG Telechat date: 2015-09-17

Summary: Almost Ready

Thanks for resolving my comments on the -05 version of this document.

Remaining Concern:

Building on the comment from my previous review on Section 5.2, Step 1:

Your response said, "The sort is done in the per-LAALP base. It's not
necessary to make the LAALP ID to a constant length. Besides, the 'mod'
function always returns a value in [0, k-1] whatever the length of
LAALP ID is."  The role of the 'mod' function was clear to me.

In Section 5.2, Step 1, the updated text says, "System ID and LAALP ID
are considered as byte strings", but the Step 2 text refers to "the
numerically sorted list".  If all of the System IDs are the same
length, then these are obviously the same.  Is that always the case?